8x^2-20=63x

Solution for 8x^2-20=63x equation:

8x^2-20=63x

We move all terms to the left:

8x^2-20-(63x)=0

a = 8; b = -63; c = -20;
Δ = b2-4ac
Δ = -632-4·8·(-20)
Δ = 4609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{4609}}{2*8}=\frac{63-\sqrt{4609}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{4609}}{2*8}=\frac{63+\sqrt{4609}}{16}
$